MATH SOLVE

3 months ago

Q:
# A car traveling at 32 m/s starts to decelerate steadily. It comes to a complete stop in 14 seconds. What is its acceleration?

Accepted Solution

A:

We have:

Initial velocity (u) = 32 m/s

Final velocity (v) = 0 m/s ⇒ The value is zero because the car comes to stationary position when it stops

Time = 14 seconds

We can use one of the constant acceleration equation:

[tex]v=u+at[/tex] where [tex]a[/tex] is the acceleration

[tex]0=32+14a[/tex]

[tex]32=-14a[/tex]

[tex]a=- \frac{32}{14}=-2.3m/s^{-2} [/tex]

The acceleration is 2.3 m/s⁻² and the negative sign shows deceleration

Initial velocity (u) = 32 m/s

Final velocity (v) = 0 m/s ⇒ The value is zero because the car comes to stationary position when it stops

Time = 14 seconds

We can use one of the constant acceleration equation:

[tex]v=u+at[/tex] where [tex]a[/tex] is the acceleration

[tex]0=32+14a[/tex]

[tex]32=-14a[/tex]

[tex]a=- \frac{32}{14}=-2.3m/s^{-2} [/tex]

The acceleration is 2.3 m/s⁻² and the negative sign shows deceleration