Apollo 8 orbited the moon in a circular orbit. Its average altitude was 185 km above the moon's surface. Create an equation to model the path of Apollo 8 using the center of the moon as the origin. Note that the radius of the moon is 1,737 km.a. x^2+y^2=34,225b. x^2+y^2=2,408,704c. x^2+y^2=3,017,169d. x^2+y^2=3,694,084

Accepted Solution

You probably haven't learnt this but the general equations for circle with centre at the origin is x^2+y^2=R^2 where R is the radius of the circle so R^2=(1737+185)^2.I am lazy to press my calculator so type it in yourself.